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or actually ask the TFs in section to hand out a meter exercise that you can do for next week.
或者是叫助教在课间,发下个星期你们要做的关于节拍的作业。
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So when you go, for example, in your neighborhood, if there's one coffee shop and you like their coffee,
所以，举个例子来说，如果你住的小区有个咖啡店，而你又喜欢喝咖啡的话，你可以去，
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So let's have a clicker question here on how many total pi bonds do you expect to see in benzene?
让我们来做个课堂习题,你们觉得苯环里有一共多少个π键？
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It has 125 assistants to the neutron, it has 75 vice neutrons and 111 assistants to the vice neutrons.
周围有125个辅助中子，有75个副中子和,111个辅助副中子。
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Well here is my array of 8, you know what, it's too much work to sort all 8.
这是有8个杯子的一个序列，要对这8个杯子进行排序就会花费较大功夫。
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My parents had a CB radio and they had a police scanner.
我父母有个汽车对讲电话,并且有个警用扫描仪。
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Then as you move out to the equity markets where it's harder to price things as efficiently--large-cap stocks -there are two-fold percentage points,first to third quartile.
如果你转而观察,难以有效定价的市场,比如大盘股,第一和第三个四分位数相差2个百分点
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They put together a documentary, and in one of the scenes it's a camp place called Drancie, which is out near the airport, halfway to the airport, to Roissy Airport.
有人把两个和起来做了个纪录片,有个镜头是在一个集中营叫德朗西,在机场附近,不到机场,戴高乐机场
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A seed,a strength,a virtue,a competence that other teachers did not see, because they did not ask this question; because they asked,metaphorically speaking, ?" "how many geometric shapes do you see on the screen?"
潜能，优点，品德，能力,这些是其他老师没看到的，因为他们没提出这个问题;,打个比方，他们只会问，“你在屏幕上看到多少个几何图案“
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It's important... I think this is the crucial point... that when we say a person is just a body, we don't understand that to mean... the physicalist doesn't mean that as-- a person is just any old body.
有个重要的一点...,我觉得这是最关键的一点,就是当我们说人只是个肉体时,我们不知道这意味着...,物理主义的意思不是...,人只是随随便便的某种肉体
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It's also interesting that Athens has a very clear tradition of thinking they had kings, and what I think is very telling is the story they give us about how kingship came to an end in Athens.
这很有趣,雅典人有个非常鲜明的传统,认为他们有过国王,他们有个我觉得很生动的故事,描述雅典的王权是如何终结的
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You have- and another example of that that would be true, is let's say you have a child who lives in this sort of circular area here, who lives here and his friends with a child who lives here.
我们还有个现实案例,假如你有个小孩,居住在我画圈的这块区域,他住在这儿,而他的朋友们住在这儿
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And then the number of pairs at month n is the number of pairs at month n - 1 plus the number of pairs at month n - 2.
我们让第一个月的兔子数是1对,第n个月的兔子对数,是第n-1个月的兔子对数。
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So that means that if we have three orbitals, we can only have six electrons in those complete three orbitals.
所以那意味着如果我们有3个轨道，我们有且只能有6个电子,在这3个完整的轨道。
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I've got two states here, three states here, two here, I need four, and if I can come up with these bonds, four, by the Hund rule I'd fill them like this.
我们已经有2个状态在这里，3个在这里，2个在这里，我需要4个，如果我能想到这些键，四个，通过洪特规则，我们就能像这样排布。
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Angular nodes, we're not going to have any of those, we'll have zero, l equals 0, so we have zero angular nodes.
角向节点，当然,是没有的，０个，ｌ等于０，所以是０个角向节点。
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So we know that it's 1, because we have 1, 2, 3, 4 bonding, minus 2 anti-bonding, and 1/2 of that is a bond order of 1.
我们知道它是，因为我们有1，2，3，4个成键，减去2个反键，它的一半就是键序为1。
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That is only option 1. We have like 9 more slots to fill.
这只是1个选择，我们还有9个其他选择。
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So similarly, as we now move up only one more atom in the table, 3 so to an atomic number of three or lithium, now we're going from six variables all the way to nine variables.
类似地就像我们现在,移动到周期表中仅仅多一个电子的情况，移动到一个原子数为，或者锂元素,现在我们从6个变量到了9个变量。
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Our step three is to figure out how many bonding electrons that we need, or excuse me, how many total electrons that we need to fill up our octets, so that's just going to be 4 times 8, which is 32.
我们的第三步是判断,我们需要多少个成键电子，不好意思，是我们总共需要多少个电子,才能填满所有“八隅体“,那么这就应该是四乘上八，也就是三十二。
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Yup, we also have six of these, because we have six carbon hydrogen bonds.
嗯，6个，因为我们有6个碳氢键。
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For example, you could put a dam in the middle of the tank.
举个例子,在水槽中间放个屏障。
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They start glomming together, but they don't stop with one plus one.
它们开始相互吸引，但是并不以1个吸引1个的形式结束。
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Yup, I heard one, so 2 minus 1, one total node.
嗯，我听到有人说１个，２减去１，１个节点。
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So supposed that I give you 16 elements to sort, well, following the logic before, the running time involved in sorting 16 elements is gonna be twice the running time 16 of sorting 8 elements, left half and right half plus 16 - and again, a little sanity check, 16 means-- just the merge steps, right?
现在要对16个元素进行排序，根据之前的逻辑，对16个元素排序,要花的时间是对8个元素排序所花时间的,2倍，分别用于左半部分和右半部分，再加上6,这里16是-,做合并的步数，对吗？
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Maybe on average institutions lose thirty basis points, but it's kind of Lake Wobegon, where we all believe that we're better than average, so we're going to overcome that thirty basis points -that's not such a big hurdle.
可能平均每个机构都会落后30个基点,这就有点像沃比冈湖效应,大家都觉得自己能高过市场平均水平,30个基点会赶上的,不算什么大的差距
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So, in terms of finishing our Lewis structure, we're actually not done yet here, even though we have full octets, and we've used up all of our valence electrons, and the reason is because it's c n minus, so we need to make sure that that's reflected in our Lewis structure, so let's put it in brackets here, and put a minus 1.
那么，根据我们的路易斯结构的完成情况，我们实际上还没有全部完成，尽管我们有了填满的“八隅体“,而且用完了所有的价电子，原因就是因为这是一个负离子，我们需要确保我们的路易斯结构能反映出这一点，所以让我们给它加个括号，再加个负一。
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So we can think about now doing bonding, and now we have four equal orbitals with one electronic each.
我们现在可以考虑成键了，现在我们有4个等价的轨道，每个上面有1个电子。
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So if you have a great idea, you know, talk to a good patent attorney and get it locked away.
所以当你有个好点子的时候，你们知道的，找个专利代理人,然后把它好好藏起来吧。
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