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Because I really want to understand what it is like for a son and a father to relate each other.
因为我很想让知道,一对父子,是如何默契相连的。
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And you find these really beautiful jade earrings and there is a specific shape
你发现了一对非常美丽的玉耳环，它有着很别致的形状。
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It is going to give me back a tuple a collection of two things, and so check out the syntax.
它将给我返回一个数组或者系列的一对值,然后检查一下语法。
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Not so much as long as the single line But in fact groups of lines. The quote editions are Highly condensed; the folio edition are probably Come closer to the full play.
不一定是一句台词,而是大段的台词，引语版是,高度浓缩的，第一对开本可能,更接近完整的剧。
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What would be the probability that a married couple would live, both of them, to the time when their children were grown?
一对已婚夫妇双双活到,孩子成年之后的概率是多少呢
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Now you have a set of parentheses as we'll see int i=0 in actual code and then I have int I equal 0.
你将会在实际的代码中看到一对圆括号,比如，我们让。
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So it looks a lot less messy if we just draw our Lewis structure like this for h c n, where we have h bonded to c triple bonded to n, and then a lone pair on the nitrogen there.
这看起来整洁了不少,如果我们把氰化氢的路易斯结构画成这样的话，这样我们就有氢与碳之间的单键和碳与氮之间三键，然后还有一对孤对电子在氮这里。
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So, when you go to two dimensions, you need a pair of numbers.
因此在二维空间里,你需要一对数字来描述
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They will always be remembered as the two brothers in the dialogue.
他们将永远被记得,是对话录中的一对兄弟。
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If somehow you could take your anti-sense molecules that you've made and you could get them into cells, then by this process of hybridization they would naturally form a pair like this.
如果你能得到合成的反义链,并能使它进入细胞,那么通过杂交,它们就能自然形成这样的一对
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I know the energy in this first pair would equal -e^2 That is just going to equal minus e squared over 4 pi epsilon zero r naught.
我们明白第一对的能量将会等于,等于,/4πε0，R圈。
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Suppose we just remove stops, and the system slams up against the other stops.
假设我们要离开挡板，系统会上升达到另一对挡板。
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A couple over it is red and so forth.
另有一对是红色的等等。
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I've been recording my first couple of demos just this week, some on Monday,
我这周录了我的第一对小样，在周一，
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So look at now has the first folio edition slide And this is actually digitized version at high resolution of that particular quotation from Hamlet and then it goes on in the normal way.
这张是第一对开本的幻灯片,这是电子版,高分辨率的是那句哈姆雷特经典台词,其他照旧。
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That expression, or that value, or that value, literally gets passed back out of that local environment to the value that comes back out of it. So in particular, none none what's solved returns is a pair.
这个表达或者说值，实际上是从那个局部环境中,输出来付给它的,所以solved返回的是一对值，它可以是一对。
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We have to pair that with that other evocation of the landscape to see this alternate idea, that actually this distanced criss-crossing of the landscape could be damaging. Think of those other violent knight's moves, like skipping past the mother's death.
我们得把关于风景的另一个回忆组成一对去理解,这个额外的想法，这个疏远的,十字纵横的景色描写可能是毁坏性的，想想其他的暴力的,迂回前进，比如跳过母亲死亡的方式。
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Initial position is a pair of numbers.
初始位置是一对数字
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OK, so what have I done? I just added a little bit more now. I'm now running through a pair of loops. Again notice the encapsulation, that nice abstraction going on, which is what I want. Once I get to this stage though by the way, there might be more than one solution.
我现在运行了一对循环,再一次注意这个封装,抽象得很好，这就是我想要的结果,我按这种方式走到这一步的时候,可能会有多组答案。
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And what we have left here is the sulfur, which will also get a pair.
剩下的是硫，它也应该得到一对。
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Because you know the energy of one pair.
因为你们知道一对的能量。
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There are also survivorship policies that will pay, for example, the second to die-- there would be a policy if a husband and wife get it, then it pays out when the second of them dies.
还有一种叫做生死两全保险,它会向身故受益人赔付直至其死亡,若一对夫妻购买这种保单,且其中一方死亡,那么它会给活着的一方赔付直至其死亡
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with someone else who's standing next to you, you're going to sum your numbers together and one of you whoever is fastest probably is going to sit down and the other person is going to take on his or her number, the summation of those numbers; and then you're going to repeat and if you follow the logic here in just a few moments, there should be just one of you very awkwardly standing.
你们需要与站在你下面一个的你结成一对,把你们的数字相加,你们中最快的那个可以坐下,其他人将接着他的那个号码继续进行，计算这些数字的和，以此重复,如果你们遵循了这一逻辑，最后将只有一个人呆呆地站着。
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So, we see is when we use the octet rule to look at fluorine molecule, we're combining two fluorine atoms, and what we end up with is an f f molecule where they're sharing two electrons, so making that covalent bond.
那么，我们看到把八隅体规则用到氟分子上,就是把两个氟原子组合起来，最终得到的氟分子中两个原子,共用一对电子，这就构成了共价键。
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So, a pair or collection of those two values.
因此一对或者一系列的两组值。
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We have another pair of stops.
这有另外一对挡板。
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And if we put that in our bond here, we have 1, 2, 3 bonds, plus we have one lone pair left over.
如果我们把它们放到键里，我们有1，2，3个键，还剩下一对孤对在这里。
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Now if you look at the quotes and the folio edition There're many cases where there are significant diversions.
现在假如你看第一对开本和引语本,还有很多很不一样的地方。
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