The stuff that's inside the reacting volume, and whatever's right around it there inside the big box, it's all going to heat up.

都会升温，对吧？,在反应容器里的东西,以及大箱子里的任何东西，他们都会变热。

麻省理工公开课 - 热力学与动力学课程节选

And it's for that whole unit that you've got some heat capacity. How much heat does it take the warm the entire thing up or the insides of the thing up by a degree? It's that number right.

由这个单位你能知道,一些热容的信息，要让这整个装置,或里面放置的东西,升温一度需要多少热量？

麻省理工公开课 - 热力学与动力学课程节选

As I'm sure you know, we're able, with various lower organisms, to put them in a state of suspended animation and then, the amazing thing is, if you heat them back up again properly, they start functioning again.

我想你们一定知道，我们能够使各种低等生物，进入假死状态,而后令人称奇的是，如果将它们正确地重新升温，它们又会重新恢复功能。

耶鲁公开课 - 死亡课程节选

It's going to be the same temperature V+dV as before but the volume is V plus dV now.

将升温到跟路径1的结果一样,但是现在的体积是。

麻省理工公开课 - 热力学与动力学课程节选

And on the other side of that temperature you end up heating if you compress.

而在另一边的温度上,压缩气体将导致升温。

麻省理工公开课 - 热力学与动力学课程节选

I'm going from T1 to T2, and I have two ways to go here. One is non-adiabatic.One is adiabatic.

从T1升温到T2有两类途径,非绝热，或者绝热。

麻省理工公开课 - 热力学与动力学课程节选

Compression you're expected to heat up, right?

压缩会升温，没错吧？

麻省理工公开课 - 热力学与动力学课程节选

Or I could have a non-adiabatic, I could take the same temperature change, by taking a flame, or a heat source and heating up my substance. So, clearly q is going to depend on the path.

也能改变温度，绝热指的是没有热传递，在非绝热条件下，也同样可以升温,比如用火或者热源加热，这样，q也应当与路径有关。

麻省理工公开课 - 热力学与动力学课程节选