This makes the IntegrateInt process update the running total to 1 (the previous total) + 2 (the new value) = 3 and write this integer out onto channel b.
这使IntegrateInt 进程把汇总值更新为1 (前一个汇总值) +2 (新值) =3并把这个整数写入通道 b。
This makes the IntegrateInt process update the running total to 1 (the previous total) + 2 (the new value) = 3 and write this integer out onto channel b.
这使IntegrateInt 进程把汇总值更新为1 (前一个汇总值) +2 (新值) =3并把这个整数写入通道 b。
应用推荐