But, we have the constraint, a equals b cosine theta.
但是我们有约束条件，a=b*cosθ
On the other hand, actually, even worse: this thing might not even be well defined. Because if the width of a equals the height of b, we can do this product.
再者说，更糟糕的是：，这个东西甚至不能很好地下定义，因为，如果A的宽和B的高相等，我们可以这样乘。
B We just compute: X equals a inverse B.
我们只用这样算：X等于A逆乘。
X It's a matrix times some unknown vector, x, B equals some known vector, B How do we solve that?
是一个矩阵乘以一些未知的向量，等于一些已知的向量，怎么解？
X It's a matrix times some unknown vector, x, B equals some known vector, B How do we solve that?
是一个矩阵乘以一些未知的向量，等于一些已知的向量，怎么解？
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