But, we have the constraint, a equals b cosine theta.
但是我们有约束条件,a=b*cosθ
B We just compute: X equals a inverse B.
我们只用这样算:X等于A逆乘。
X It's a matrix times some unknown vector, x, B equals some known vector, B How do we solve that?
是一个矩阵乘以一些未知的向量,等于一些已知的向量,怎么解?
There's just A equals B, that single thing.
就只有A等于B,那一个东西
pV=RT p plus a over v bar squared times v bar minus b equals r t. All right if you take a equal to zero, these are the two parameters, a and b. If you take those two equal to zero you have p v is equal to r t.
我们就回到,也就是理想气体,状态方程,下面我们来看看,这个方程。
This will generalize to probability of A and B and C equals the probability of A times the probability of B times the probability of C and so on.
简单的说,A和B和C同时发生的概率,等于A发生的概率乘以B发生的概率,乘以C发生的概率,以此类推
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