That's why we need independence of the central bank; we want to have a central banker that can say no to the government.
这就是为什么我们需要独立自主的,中央银行;,我们希望有一个可以对政府说不得,中央银行家。
It's... I mean, this is what we need to be doing.
这就是我们需要做的。
All right, so this is the same procedure that we're going to go through, regardless of what kind of Lewis structure we're going to draw.
好的,这就是我们画路易斯结构,所需要完成的步骤,不管什么样的路易斯结构都要这样做。
Here is what we calculate to tell whether it happens spontaneously.
这就是我们所需要计算的物理量,它能够告诉我们变化是否会自发发生。
So that's the dialectic; that's what's negotiated.
那就是对立,这就是我们需要跨越的。
And, that's all we need to do.
这就是所有我们需要做的。
So what we're going to do is take the equations for those two lines, so here's one of those equations and here's the other one, set the P in those equations equal to X, I've got two equations in one unknown, I'm sorry, I've got one equation and one unknown.
接下来我们只需要,列出这两条线各自的方程,也就是这个方程和这个方程,把方程中的P换成X,我就得到了两个等式和一个未知数,错了,是一个等式和一个未知数
So, in terms of finishing our Lewis structure, we're actually not done yet here, even though we have full octets, and we've used up all of our valence electrons, and the reason is because it's c n minus, so we need to make sure that that's reflected in our Lewis structure, so let's put it in brackets here, and put a minus 1.
那么,根据我们的路易斯结构的完成情况,我们实际上还没有全部完成,尽管我们有了填满的“八隅体“,而且用完了所有的价电子,原因就是因为这是一个负离子,我们需要确保我们的路易斯结构能反映出这一点,所以让我们给它加个括号,再加个负一。
Convention, OK, this negative sign is just a pure convention. You just got to use it all the time. If you use an old textbook, written when I was taking thermodynamics, they have the opposite convention, and it's very confusing. But now we've all agreed on this convention, and work is going to be with the negative sign here.
系统对外界做功的符号为负,这就是我们,在本课中的规定,纯粹出于统一符号的需要,有些教科书中,可能会使用相反的符号规定,注意不要混淆了,这门课上,我们将一直使用。
So what we'll end up with is boron plus, 1 s 2 2 s 2 1 s 2, 2 s 2, E and what we say is the delta energy or the change in energy as the same thing as saying the energy of the products minus the energy of our reactant here, that's how much energy we have to put into the system to eject an electron.
所以结果应该是正一价的硼,电子排布为,我们说,Δ,也就是,E,的变化量,等于生成物的能量,减去反应物的能量,这就是我们从这个系统中,打出一个电子所需要的能量。
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