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So, regardless of the type of wave that we're talking about, there's some common definitions that we want to make sure that we're all able to use, and the first is amplitude.
所以，不管我们讨论的,是哪种波，它们都有一些我们,能用到的共同的定义,其中第一个就是幅值。
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In that case point p 1 doesn't correspond to this point, it actually corresponds to the point of radius 2 and angle 1, which is about here.
基本上也就是说这是第一个点1,这是第二个点，把它们的值加到一起,然后我就得到了目标点，好，这听起来挺不错的。
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This first number here gives the value of n.
这里的第一个数字是n的值。
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You want to subtract off the value of a perpetuity that starts after 2T, six-month intervals, so this is the present value of the perpetuity that starts after 2T, six-month intervals.
所以就要从永续债券价格里减去,2T期以后,每六月一期券息的贴现值,这部分是永久债券从第2T期后,每半年一期券息的现值
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If you go and work that out, log2 log of two and you have two log two, by math you can show that for the line r series m 2*log2 is equal to two natural log of two, which is 1 1.386 which is greater than one.
如果你把它计算出来，这二者的对数，你会得到2个，通过数学，你会得到第r列，第m个值,等于,也就是1。386，这大于。
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First line says, 0 if i is 0, that means I'm looking at the very last element.
第一行的意思是，如果i的值是，就意味着我看到的,是最后一个元素。
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Notice in the class definition here, is there, this is the first thing that's got called, and I just called with the value for x and the value for y, and it went off and did something for me.
就在这里，这是第一个被调用的东西，我用x的值和y的值调用了它,然后这个方法继续进行，并为了做了一些操作。
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All right, first question. What values of x does it terminate? Again, assume x is an integer.
好，第一个问题，对于x的什么值程序,会最终终止，还是假设x为整数。
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The first statement right here, that's just an assignment statement, I'm giving some value to x.
第一个声明在这里，这仅仅是一个赋值声明，我赋值给x一个值。
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Is the first part. That says, I took the branch through here that eventually got to the end and said, there wasn't a solution, in which case I'mgoing to print out, there ain't no solution, otherwise I'll print out the pieces. All right, let's check it out. Ah, what did I say?
我是否返回了特殊的none值？是第一部分,这里的意思是我从这个分支,走到这儿最终走到最后，并告诉我这条路没有解决方案，也就是我想要打印的结果,没有符合的结果，否则我会把它们输出来？
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