If I now hybridize these, if I take these and I make four symmetric, now, these are just the sp3 orbitals.
如果我将他们杂化,然后形成4个对称的轨道,这就是sp3轨道。
This bond is polar, but again, as I alluded to earlier, because the carbon is centered in the tetrahedron, because of the sp3 hybridization, the molecule itself is symmetric and nonpolar.
这个键是非极性的,但是,我们断言过早,因为C是中心原子,由于sp3杂化,这个分子本身是非极性的且对称的。
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