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And what we find out is the wavelength of a Matsuzaka fastball is 1.1 times 10 to the -31 meters.
我们算出松阪快球的波长,是1，1乘以10的负31次方米。
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And what we end up with for the energy then is 2.84 times 10 to the -19 joules.
我们算出的能量是,2，84乘以10的-19次方焦耳。
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Three plus five. I can take something to a power, double star, just take three to the fifth power.
+5，我也可以,求一个数的次方，例如求3的5次方。
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And if you noticed earlier that these are what we'd call powers of ten, these are just powers of two.
四位，八位吗？,如果你想想之前学习的十的次方，这些就是二的次方。
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It is not an SI unit because it is not a multiple of 10 to the 3rd, but I like the angstrom.
它不是国际制单位，因为它不是,10的3次方进制，但我还是喜欢这个单位。
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T1 Anyway T2 over T1 is equal to V2 over V3 to the power gamma minus one.
总之，T2除以3,等于V2除以V3的伽马减一次方。
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If the probability is 1 in 1,000 that a house burns down and there are 1,000 houses, then the probability that they all burn down is 1/1000 to the 1000th power, which is virtually zero.
如果一栋房子着火的概率是千分之一,然后假设有1000栋房子,那么这一千栋房子全都着火被烧掉的概率,就等于千分之一的一千次方,基本上就是0了
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And then we have c, the speed of light, 2.998 times 10 to the 8 meters per second.
然后我们知道光速等于，2，998乘以10的8次方米每秒。
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If we think about the size of a typical cell - excuse me, now I'm getting confused about nuclei.
它大约是10的,负十四次方米，如果我们考虑。
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So if you're not in this 77%, let's quickly go over why, in fact, this is the correct answer, . 9 times 10 to the negative 18 joules.
如果你们不在这77%中，让我们快速的来看一看为什么，这个是正确答案，0，9乘以10的负18次方焦耳。
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So now we can just take the negative of that binding energy here, and I've just rounded up here or 1 . 4 times 10 to the negative 19 joules.
等于4是第三激发态,现在我们可以取它结合能的负值,也就是1。4乘以10的负19次方。
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What do you think the error is going to be by failing to recognize that at the end of 6 times 10 to the 23rd I have over-counted some energy?
你们可能会发现，这将会有误差,在6乘以10的23次方的末端,我多余地引入了一些能量？
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So it's 2 to the 32, 'cause remember a bit is a 0 or 1.
就是2的32次方，因为1比特只能表示0或。
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This is 10 to the minus 18 joules for this one atom.
对单个原子，就是10的负18次方焦耳。
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That means our energy is equal to 6.626 times 10 to the -34 joules times seconds.
这意味着能量等于,6，626乘以10的-34次方焦耳每秒。
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So for every photon we have 2.84 times 10 to the -19 joules.
每一个光子有,2，84乘以10的-19次方焦耳。
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That quantity in parenthesis, I have a mass which is a positive number. Something raised Something raised to the fourth power has got to be positive.
顺便说一句,质量这个量是个正数,四次方的值,肯定是正数。
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So, we would actually need a really, really, really tiny velocity here to actually overcome the size of the mass, if we're talking about macroscopic particles, to have a wavelength that's going to be on the order.
是10的负34次方焦耳每秒,所以如果我们谈论的是要一个，宏观粒子有相应数量级的波长的话，我们需要一个非常非常非常小的速度来。
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Instead of summing them and dividing by M, I multiply them all together and take the nth root of them.
我把所有的乘在一起然后开n次方,而不是把他们加总再除以个数
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If n is something like 50, not a big number, 2 to the 50 is a huge number.
如果n是50，50不是一个大数，但2的50次方就是一个巨大的数。
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OK. If b is even, then a to the b is the same as a squared all to the b over 2.
就等于a的平方的二分之b次方,好，就是把二挪到外面来了。
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In the linear case, meaning in the unsorted case what's the complexity of this? k times n, right? Order n to do the search, and I've got to do it k times, so this would be k times n.
复杂度是多少？k的n次方，对吧？,在序列n中做搜索，要做k次，所以是k的n次方次,如果先排序后搜索。
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And in the even case, I'd square, divide by half, call this again: in the odd case, I go b minus 1 and then multiply by a.
就直接求a的平方的二分之b次方，如果是奇数的话，就去求a的b-1次方乘以a，以此递归下去。
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At very, very low values of r, one over r to the 10th dominates.
在很小很小的r是，1/r的10次方占主导。
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Well let's see, there's a V1 over V2 to the gamma minus 1.
现在来看，这边是V1/V2的γ-1次方。
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So 1.1 times 10 to the -31 meters is not, in fact, a significant number when we're comparing it, for example, to the length of a ball, or the size of the baseball field.
所以1，1乘以10的负31次方米，事实上并不是一个很重要的数字，举例来说，当它与一个球的长度，或者一块棒球场地对比时。
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So, keep in mind that one milliwatt is just the same as saying 1 times 10 to the -3 joules per second.
所以，请记住1毫瓦,和1乘以10的-3次方焦耳每秒,的说法是等同的。
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So, if we do this calculation for an electron, saying it moves at 10 to the 5 meters per second, then what we end up with for a wavelength is 7 times 10 to the -9 meters.
如果我们已知电子以，10的5次方每秒的速度运动，那么做一个计算,可以得知它的波长是,7乘以10的负9次方米。
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So if I have 32 bits, each of which can be a 0 or 1, that's two possibilities for every place, so 2 to the 32, that's 4 billion.
如果有32比特的话，每个比特都有0或，两种可能性，所以是2的32次方，也就是40亿。
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