So you know from algebra I can't actually solve this. There may be multiple solutions to this. What would I have to do to change my code? And the answer is fortunately not a lot.
我解不出来方程,可能会有多组答案,我需要怎样修改我的代码呢?,很幸运的,答案是不用修改很多。
We've looked so far really at two non-scalar types. And those were tuples written with parentheses, and strings.
关于这两种基本类型我们已经,学的相当多了,包括哪些元组和字符串类型。
It turns out that the group that had--were paid a dollar rated the task as much more fun than the group given twenty dollars.
结果发现,拿一美元的那组对这个任务的评价,要比拿20美元的那组高得多。
OK, so what have I done? I just added a little bit more now. I'm now running through a pair of loops. Again notice the encapsulation, that nice abstraction going on, which is what I want. Once I get to this stage though by the way, there might be more than one solution.
我现在运行了一对循环,再一次注意这个封装,抽象得很好,这就是我想要的结果,我按这种方式走到这一步的时候,可能会有多组答案。
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