• So, in order to fill our octet, what we do is put two on the nitrogen and two on the carbon.

    因此,为了填满我们的““,我们需要将两个放到氮上,将另外两个放到碳上。

    麻省理工公开课 - 化学原理课程节选

  • So in order to fill them, he would have to have eight electrons or an octet around the cubes.

    因此为了填满它们,他必须放上个电子或者说一个““,在立方周围。

    麻省理工公开课 - 化学原理课程节选

  • We'd have to figure out a way to achieve octet stability by electron transfer.

    我们需要找到一个可以通过电子转移,而实现的方式。

    麻省理工公开课 - 固态化学导论课程节选

  • So in terms of total numbers that we would need to complete our octets and fill our valence shells, we would need 18 electrons.

    因此要填满我们的““,排满所有的价壳层,我们总共需要十个电子。

    麻省理工公开课 - 化学原理课程节选

  • So this is the idea of the octet rule that Lewis came up with way back in 1902.

    这就是所谓的规则,是路易斯在,1902,年提出来的。

    麻省理工公开课 - 化学原理课程节选

  • So, if you look at all of these, we have full octets for all of them, and if we count up all of the valence electrons, it's going to be equal to our number 26 here.

    那么,如果大家看看所有的这些,它们的““都填满了,而如果我们来数一数价电子的总个数,它应该就等于我们这里的二十六。

    麻省理工公开课 - 化学原理课程节选

  • And all we need to do is go over here now and fill up our octets.

    而我们所需要做的就是到这里来,把我们的““都填满。

    麻省理工公开课 - 化学原理课程节选

  • Yes. Definitely, because both of these are not anywhere near filling up their octets yet.

    应该,肯定的,因为它们两个都还没有,填满它们的“

    麻省理工公开课 - 化学原理课程节选

  • Our step three is to figure out how many bonding electrons that we need, or excuse me, how many total electrons that we need to fill up our octets, so that's just going to be 4 times 8, which is 32.

    我们的第三步是判断,我们需要多少个成键电子,不好意思,是我们总共需要多少个电子,才能填满所有““,那么这就应该是四乘上,也就是三十二。

    麻省理工公开课 - 化学原理课程节选

  • So, we see is when we use the octet rule to look at fluorine molecule, we're combining two fluorine atoms, and what we end up with is an f f molecule where they're sharing two electrons, so making that covalent bond.

    那么,我们看到把规则用到氟分子上,就是把两个氟原子组合起来,最终得到的氟分子中两个原子,共用一对电子,这就构成了共价键。

    麻省理工公开课 - 化学原理课程节选

  • And if we go on to step three where we figure out how many we would need for full octets, it's just going to be 2 times 8, so we have 16.

    而如果我们继续到第三步,判断一下填满所有““需要多少个价电子,结果应该就是二乘以,也就是十六个。

    麻省理工公开课 - 化学原理课程节选

  • The nitrogen. The reason being that's the only one that didn't have a full octet yet.

    氮,因为只有它的““,还没有填满。

    麻省理工公开课 - 化学原理课程节选

  • But that each individual fluorine atom has eight electrons, or full octet around it.

    但是每个氟原子现在都有个电子,或者说周围有一个填满的

    麻省理工公开课 - 化学原理课程节选

  • And, we have achieved octet stability in the same way.

    我们也同样实现了

    麻省理工公开课 - 固态化学导论课程节选

  • So, if we're talking about hydrogen, that's our one exception so far to the octet rule.

    那么,如果我们讨论的是氢原子,它是目前我们遇到的规则的唯一例外。

    麻省理工公开课 - 化学原理课程节选

  • So, the octet rule is a general rule that you'll for all of the atoms.

    因此,规则是一条普适的规则,对于所有原子来说都是。

    麻省理工公开课 - 化学原理课程节选

  • So I said that we want to be talking about valence electrons here, so that means if we're talking about, for example, the octet rule for an f f molecule where we have two fluorine atoms, we need to write the valence electrons as dots around them.

    我说过我们在这要讨论的是价电子,这就意味着,如果我们要讨论,比如,关于两个氟原子组成的分子的规则,我们首先需要把价电子画成围绕在它们周围的点。

    麻省理工公开课 - 化学原理课程节选

  • And as a result of that, the achieving of octet stability via electron transfer tumbled to the idea of an ionic bond where one atom donates an electron completely to the other atom, sort of like servanthood.

    有了他们,也就是形成的稳定结构,通过电子的扰动形成理想的离子键,这儿一个原子完全将一个电子,给另一个原子,有点像奴仆关系。

    麻省理工公开课 - 固态化学导论课程节选

  • So remember, that when we talked about Lewis structure, the organizing principle behind Lewis structures is the idea that within the molecule the atoms are going to arrange their valence electrons, such that each atom within the molecule has a complete octet or full outer shell.

    记得,当我们讨论路易斯结构的时候,路易斯结构所遵循的组织原则是这样一种思路,那就是分子中的原子都倾向于,重新安排它们的价电子,使得分子有一个完整的,““或者排满的外壳层。

    麻省理工公开课 - 化学原理课程节选

  • So, in terms of finishing our Lewis structure, we're actually not done yet here, even though we have full octets, and we've used up all of our valence electrons, and the reason is because it's c n minus, so we need to make sure that that's reflected in our Lewis structure, so let's put it in brackets here, and put a minus 1.

    那么,根据我们的路易斯结构的完成情况,我们实际上还没有全部完成,尽管我们有了填满的““,而且用完了所有的价电子,原因就是因为这是一个负离子,我们需要确保我们的路易斯结构能反映出这一点,所以让我们给它加个括号,再加个负一。

    麻省理工公开课 - 化学原理课程节选

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