• So 2 billion, 4 billion -- these are big numbers, but there's a lot of "billions of things" in the world, right?

    所以20亿,40亿--这都是很大的数值,但是世界上有很多“数十亿的东西“,对不?

    哈佛公开课 - 计算机科学课程节选

  • So we can go right ahead and fill these in. 1 2, 3 4, 5 and 6.

    一,二,三,四,五和六。

    麻省理工公开课 - 化学原理课程节选

  • So the strategy choices, we're not going to do it in hours, let's just normalize and regard these choices as living in 0 to 4, and you can choose any number of hours between 0 and 4.

    我们用小时数来表示策略吧,用0到4的数字来标记这些策略,你可以从0到4中任选工作的小时数

    耶鲁公开课 - 博弈论课程节选

  • Do you realize that this is a pair of simultaneous equations in which you can solve for these two unknowns, if you like, in terms of these two knowns and these coefficients, which are like these numbers, 3, 2, 4, and 6?

    你们是否发现这其实就是一个方程组,你可以用它来解出这两个未知量,你愿意的话,可以用这两个已知量,和这些系数,比如这些数字,3,2,4和6

    耶鲁公开课 - 基础物理课程节选

  • During the section times I'll be available if you feel like you want to read Chapters 2 and 4 and then come and ask questions, sort of a tutorial on these topics of chemistry and biochemistry, then I'll be available to talk about that during that time.

    在小组讨论的时间里,你们可以来找我,如果你们学习完第二章和第四章之后,想问一些关于,化学和生化方面的问题,可以来找我,我会在那个时候给你们进行讲解

    耶鲁公开课 - 生物医学工程探索课程节选

  • The pieces that we pulled off the shelf here were ultimately reduced to things like 4 loops and what we'll call functions and what we'll call abstraction; and all these fundamentals that at first glance might have some fairly RK and jargon associated with them.

    我们可以把现有的课程,分为四大领域,以及应用型课程和抽象理论课程,乍一看,所有这些基础课程,都可能会和RK及与之相关的术语联系在一起。

    哈佛公开课 - 计算机科学课程节选

  • y are these the same?

    坐标赋值为4,OK,,now,I,want,to,say,好,现在我想看看?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So what we know is that these 3 d orbitals are higher in energy than 4 s orbitals, so I've written the energy of the orbital here for potassium and for calcium.

    我们所知道的是,3d轨道能量,比4s轨道能量高,所以我写出了,钾和钙的轨道能量。

    麻省理工公开课 - 化学原理课程节选

  • The highest Player II ever chooses is 2, and the highest response that Player I ever makes to any strategy 2 or less is 6/4, so all these things bigger than 6/4 can go.

    参与人II最大只会选策略2,参与人I针对这种情况下,最大只会选择6/4,即大于6/4的策略也会被剔除

    耶鲁公开课 - 博弈论课程节选

  • To get any location in memory, to get to any value of the list, I simply have to say which element do I want to get, I know that these things are stored in a particular size multiply that index by 4, add it to start, and then it's in a constant amount of time I can go to that location and get out the cell.

    取得列表中的任何一个值,简单说来,想要取得列表中的任何元素,我知道这些元素存在特定的大小中,把下标乘以4,加到start上,然后定位到内存单元,并取出值就是固定的时间了,好的,如果元素以固定大小存储。

    麻省理工公开课 - 计算机科学及编程导论课程节选

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