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So this, where we start at zero is not a node, is the first thing to point out.
零点不是节点，这是第一个要指出来的，当我们。
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In fact, my program crashes because I end up trying to divide by zero, a really bad thing. Hint: if you implement Newton's method, do not make your first guess zero.
我下一步都没法开始,实际上，我的程序会崩溃，因为我试着去除0了，真糟糕,提示你：如果你想用牛顿的方法，第一个猜想数别设为0。
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I'm first printing the zero argument which I said is the name of the program itself.
我先打印参数,这是那个程序本身的名字。
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First let's set the external pressure equal to zero.
首先，让外部压强为零。
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First of all, happiness is a positive sum game-- it's not a zero sum game.
首先，快乐是正和游戏-,不是零和游戏。
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I know the energy in this first pair would equal -e^2 That is just going to equal minus e squared over 4 pi epsilon zero r naught.
我们明白第一对的能量将会等于,等于,/4πε0，R圈。
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Let's create a graph here that on the x axis it's going to be time, so time zero will be when you first take in a food and then one hour later, two hours later will be shown as you go from left to right, and then we'll have blood glucose level up on the y axis.
我们在这建立一个曲线图,X轴代表的是时间,所以零时间点是你第一次进食的时间,然后一小时以后,两小时以后,是从左到右呈现在图表上的,在Y轴上是你的血糖值
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First problem set, problem set zero, has already been posted.
头一条问题的提出，提出问题为零。
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Because I've hard coded the zero, it's just capitalizing they first character.
因为我硬编码了那个零，它只是把第一个字母变成大写。
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All right, we're-- well actually, I should say that better, we first check to see, is x 0 greater than or equal to zero, if it's not, then we come down here and we print something out, otherwise we run through a little loop to get the answer, and then we check it and we spit something out.
然后我们运行一个小循环,好了，我们现在来看看,如果x≥0或者x＜,我们看这儿,我们会输出一些内容,或者我们运行一个小循环来获取答案,然后我们检验一下，然后得到结果。
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V1 This first integral is zero V1 to V1, then I get minus p2 times V2 minus V1 or p2 times V1 minus V2. Again, 0 a positive number.
先保持体积为，对pdV积分1,然后对p2dV从V1到V2积分，第一部分积分为。
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