Yup, so one total node, 2 minus 1 is 1, and that means since l is equal to 1, we have one angular nodes, and that leaves us with how many radial nodes?

一个节点，２减去１等于１,因为ｌ等于１,我们有一个角向节点，那剩下径向节点有多少个呢？

麻省理工公开课 - 化学原理课程节选

And when we talk about angular nodes, the number of angular nodes we have in an orbital is going to be equal to l.

当我们谈到角向节点时，一个轨道的,角向节点数等于ｌ

麻省理工公开课 - 化学原理课程节选

l l So what you can do for a 1 s is just take 1 minus 1 and then l is equal to 0, so you have zero radial nodes.

它等于1减去,是等于0的，所以没有节点，这和我们看到的是相符的。

麻省理工公开课 - 化学原理课程节选

For an angular node, we're just talking about what the l value is, so whatever l is equal to is equal to the number of angular nodes you have.

对于角向节点，我们其实就是在讨论l，的值是多少，因此不管，l，的值等于几,它就等于你所有的角向节点的数目。

麻省理工公开课 - 化学原理课程节选

And then if we think about 3 s, 0 we want to start with 3, we subtract 1, again l is equal to 0, so minus and we have two radial nodes.

我们从3开始，减去，同样的l等于，所以减去0，我们有两个节点，这应该。

麻省理工公开课 - 化学原理课程节选