Yup, so one total node, 2 minus 1 is 1, and that means since l is equal to 1, we have one angular nodes, and that leaves us with how many radial nodes?
一个节点,2减去1等于1,因为l等于1,我们有一个角向节点,那剩下径向节点有多少个呢?
And when we talk about angular nodes, the number of angular nodes we have in an orbital is going to be equal to l.
当我们谈到角向节点时,一个轨道的,角向节点数等于l
l l So what you can do for a 1 s is just take 1 minus 1 and then l is equal to 0, so you have zero radial nodes.
它等于1减去,是等于0的,所以没有节点,这和我们看到的是相符的。
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