And then we have c, the speed of light, 2.998 times 10 to the 8 meters per second.

然后我们知道光速等于，2，998乘以10的8次方米每秒。

麻省理工公开课 - 化学原理课程节选

I first had a list of size 8, then 4, then 2, but then I had another problem of size 2.

首先是一个有8个元素的序列，接着变成了4个元素，接着2个元素，然后我就碰到了有2个元素的另一个问题。

哈佛公开课 - 计算机科学课程节选

Chapters 8 through 10 recount the installation of Aaron as high priest and the Aaronides then as the priestly clan within Israel.

到10章节讲述了亚伦是怎么成为大祭司的,以及亚伦的后代是怎么成为以色列的祭司宗族的。

耶鲁公开课 - 旧约导论课程节选

And if you have your calculator all set up as you love and you don't want to change it, then maybe you should just go and get an $8.00 scientific calculator that doesn't have any of the graphing functions, because you don't actually need them, so that's a better option for you, you can do that as well.

如果你的计算器里已经按照你的喜好编好了,而你又不想改动，那么或许你可以,去再买一个八美元的科学计算器,它没有任何绘图功能，因为实际上你也用不到这些，所以这对你来说是一个更好的选择，你也可以这样做。

麻省理工公开课 - 化学原理课程节选

Then we ruled out 3 and 8, and then we ruled out, we would have done 4 and 7 and that leaves just 5 and 6.

然后我们排除立场3和8,然后我们排除,我们应该也能排除4和7及5和6

耶鲁公开课 - 博弈论课程节选

Then you guys know, you just told me, acceleration is -9.8, We call it "minus" because it's accelerating down and up was taken to be the positive direction.

然后你们都知道,你告诉我,加速度是-9.8,我们取负号是因为加速度方向朝下,而正方向为竖直向上

耶鲁公开课 - 基础物理课程节选

Log n Log n, because at each stage I'm cutting the problem in half. So I start off with n then it's n n/2 n/4 n/8 over two n over four n over eight.

因为总共有多少层？,因为在每一层，我都是把问题分解成两半,因此以n开始，然后是。

麻省理工公开课 - 计算机科学及编程导论课程节选

Just two, I touched 6 once and then I moved ahead, and then I touched 8 and I moved ahead, not touching any other number.

只有2次，我先将6移了下来，然后将8移了下来，并没有动其他的数字。

哈佛公开课 - 计算机科学课程节选

And also I wanted to mention in terms of checking your Lewis structures, regardless of what they are, you should always go back and I had 10, and then count 2, 4, 6, 8, 10, because you always need to make sure you have the same number of valence electrons that you calculated in your actual structure.

我还想提一点关于检查,你的路易斯结构的建议，不管它们是什么，你总是应该回去检查一下,我有十个，然后数一数，二，四，六，八，十个，因为你总是需要确保实际价电子的数量,与你在结构中算出的数量相等。

麻省理工公开课 - 化学原理课程节选

6 Well again, we can go to our ones column, twos, four, eight, 16, 2 damn, 32. So we can go to 32 128 and then we can go to 64, and then 128, 1 2 3 4 5 6 7 8 and this gives me 1, 2, 3, 4, 5, 6, 7, 8.

好吧，再一次回到一位，二位，四位，八位，该死的，32，等等，所以我们可以找到32位2,再64，然后，那么我们就有了。

哈佛公开课 - 计算机科学课程节选

And in this case, we go from 8 to 4 to 2 to 1 three times and then on each iteration of this algorithm, each pass across the board I'm touching N numbers, so that means I'm doing N things, log N times.

在这个例子中，我们从8得到4，到2，再到1，是3次,在这个算法的每次迭代中，每一趟我都会操作N个数，也就是所我每次要做N步操作，一共要做，log，N，次。

哈佛公开课 - 计算机科学课程节选