• We know it's going around in a circle because if I find the length of this vector, which is the x-square part, plus the y-square part, I just get r square at all times, because sine square plus cosine square is one.

    我们之所以知道它做圆周运动,是因为我求出了这个矢量的模长,也就是 x 的平方加上 y 的平方,我就得到了它在任意时刻的模长平方,因为正弦平方加余弦平方始终等于1

    耶鲁公开课 - 基础物理课程节选

  • But since sine square plus cosine square is 1, you'll find this vector has a fixed length R.

    但是由于正弦和余弦的平方和为1,你会发现这个矢量模长恒等于 R

    耶鲁公开课 - 基础物理课程节选

  • So the square root of n squared r e over r h.

    这里的n值是什么呢?

    麻省理工公开课 - 化学原理课程节选

  • Whenever you see a particle moving in a circle, even if it's at a constant speed, it has an acceleration, v square over r directed towards the center.

    只要看到质点做圆周运动,即使是匀速圆周运动,也存在一个加速度,大小为 v^2 / r,方向指向圆心

    耶鲁公开课 - 基础物理课程节选

  • take the derivative of this, get the velocity vector and you notice his magnitude is a constant Whichever way you do it, you can then rewrite this as v square over r.

    对这个式子求一次导,就能得到速度矢量,你会发现其模长是常数,不管用什么方法,加速度也可以写成 v^2 / r

    耶鲁公开课 - 基础物理课程节选

  • If you want to write it as a vector equation, you want to write it as v square over r minus-- I want to say that it's pointing in the direction toward the center.

    如果要写出矢量方程,就应该写成 -v^2 / r,也就是说,方向就向圆心

    耶鲁公开课 - 基础物理课程节选

  • The magnitude is v square over r.

    模长为 v^2 / r

    耶鲁公开课 - 基础物理课程节选

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