One over two squared minus one over n squared 3 4 5 where n takes values three, four, five, six.
除以,2,的平方再减去1除以n的平方,将n赋值为。
Right? In other words I've got the stoichiometric coefficients in there and the values, and I'm subtracting the reactants from products -1652kJ/mol wind up with minus 1652 kilojoules per mole.
对吧?换句话说这里我用了化学,计量系数和生成热的值,从生成物中减去反应物,最后得到。
And we plug in our values and end up with mv squared mv^2/r-Ze^2/ over r minus Ze squared over And I am going to call this equation two.
我们最后的结果,就是,我把这称为方程式二。
And here d, of course, can take the values from plus three down to minus three.
而d层,当然,能够包括从+3到-3的所有值。
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