One over two squared minus one over n squared 3 4 5 where n takes values three, four, five, six.

除以，2，的平方再减去1除以n的平方,将n赋值为。

麻省理工公开课 - 固态化学导论课程节选

Right? In other words I've got the stoichiometric coefficients in there and the values, and I'm subtracting the reactants from products -1652kJ/mol wind up with minus 1652 kilojoules per mole.

对吧？换句话说这里我用了化学,计量系数和生成热的值，从生成物中减去反应物,最后得到。

麻省理工公开课 - 热力学与动力学课程节选

And we plug in our values and end up with mv squared mv^2/r-Ze^2/ over r minus Ze squared over And I am going to call this equation two.

我们最后的结果,就是,我把这称为方程式二。

麻省理工公开课 - 固态化学导论课程节选