• Club America is in second place after a 2-1 win over AC Milan on Wednesday in Atlanta and a penalty shootout win over Inter Milan last Monday in California.

    VOA: standard.2009.07.25

  • And what we end up with for the energy then is 2.84 times 10 to the -19 joules.

    我们算出的能量是,2,84乘以10的-19次方焦耳。

    麻省理工公开课 - 化学原理课程节选

  • This is, you see, also on 2 at the beginning here: I went to the cold-water flat with the boys and Dean came to the door in his shorts.

    你们看,这也是在第二页的开始:,我和男孩们去了冷水公寓,安穿着短裤来到门口。

    耶鲁公开课 - 1945年后的美国小说课程节选

  • At the February 14th auction, Treasury bills were-- sixty-day treasury bills were sold and the auction price is given.

    2月14日的拍卖中,卖出了60天期国库券期,这里给出了拍卖价格

    耶鲁公开课 - 金融市场课程节选

  • The way that we can figure this out is using something called bond order, and bond order is equal to 1/2 times the number of bonding electrons, minus the number of anti-bonding electrons.

    我们可以用叫做,键序的概念来弄明白它,键序等于1/2乘以成键电子,数目减去反键电子数目。

    麻省理工公开课 - 化学原理课程节选

  • So in Deuteronomy 5:2-3: "The Lord our God made a covenant with us at Horeb . It was not with our fathers that the Lord made this covenant but with us, the living, every one of us who is here today."

    那么在申命记5章2-3节耶和华我们的神在和烈山,与我们立约这约不是与我们祖先立的,乃是与我们今日在这里存活之人立的“

    耶鲁公开课 - 旧约导论课程节选

  • OK. If last minus first is greater than or equal to 2-- sorry, less than 2, then either look at this thing or look at that thing.

    大于等于儿,抱歉,是小于二,看看这里或者那里,这就是我说的要特别小心的地方。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • One that's . 2 kilobases long and one that's 1.1 kilobases long - kilobase is 1,000 bases.

    一段长0.2千碱基,另一段长,1.1千碱基,千碱基指一千个碱基

    耶鲁公开课 - 生物医学工程探索课程节选

  • And I'm going to get minus 2, which came from here: minus 2 and that is in fact negative, which is what I wanted to know.

    最后只剩下-2了,2是一个负数,这正是我想要的

    耶鲁公开课 - 博弈论课程节选

  • You know it is about two to three electron volts.

    你知道他们大约为2-3伏。

    麻省理工公开课 - 固态化学导论课程节选

  • For example, if t* is the time you hit the ground, then t* satisfies the equation h - 1/2 g ^2 = 0.

    例如,如果在 t* 时刻落地,那 t* 就满足等式 h - 1/2 g ? ^2 = 0

    耶鲁公开课 - 基础物理课程节选

  • So this code is identical functionally nonswitch c to the last implementation we saw, nonswitch.c, but I'm just ever-more emphatically saying, "In case 1," that is when n equals 1 -- or when case 2 applies -- when n equals 2 or when n equals 3 do what?

    所以这些代码到最后的实现上,功能是,完全相同的,但是我想要再次强调一下,“在case,1“,那是当n等于1时1,或者当case,2适用-,当n等于2或者当n等于3,它将做什么?

    哈佛公开课 - 计算机科学课程节选

  • So we know that it's 1, because we have 1, 2, 3, 4 bonding, minus 2 anti-bonding, and 1/2 of that is a bond order of 1.

    我们知道它是,因为我们有1,2,3,4个成键,减去2个反键,它的一半就是键序为1。

    麻省理工公开课 - 化学原理课程节选

  • .. The equity premium is the-- 2.8% this short-term 2.8% is the riskless return, historically, for a period of almost 200 years.

    股权溢价就是-,这个短期无风险投资收益率是,是根据近200年的数据得出的。

    耶鲁公开课 - 金融市场课程节选

  • For example, we might have--this is asset 1-- and we might have something here--this could be asset 2.

    例如,这个点表示一号资产-,这里这个点表示二号资产。

    耶鲁公开课 - 金融市场课程节选

  • - 2. So for example So our conjecture here is that 2 dominates 1.

    策略2,-例如策略2,我们推测策略2优于策略1

    耶鲁公开课 - 博弈论课程节选

  • So if we have total +2 and complete shielding -1 where that can actually negate a full positive charge, because remember our nucleus is plus 2, +1 one of the electrons is minus 1, so if it totally blocks it, all we would have left from the nucleus is an effective charge of plus 1.

    抵消一个完全的正电荷,因为记住我们的原子核是,其中一个电子是,所以如果它完全挡住了它,我们从原子核中留下的,全部有效电荷就是,所以,在我们的第一个例子中,我们的第一种极端情况。

    麻省理工公开课 - 化学原理课程节选

  • Nothing is said of Moses' childhood, But we learn of his awareness of his Israelite identity, or his identification with the Hebrews, in the following passage: this is in Exodus 2:11-15: Some time after that, when Moses had grown up, he went out to his kinsfolk and witnessed their labors.

    丝毫没有提到摩西的童年,但是我们却知道他意识到自己以色列人的身份,或者是他与希伯来人的身份关联,在接下来的《出埃及记》第2章11到15节中:,在那之后,摩西长大了,他出去看到了他的同族和他们的劳作。

    耶鲁公开课 - 旧约导论课程节选

  • py And finally, we can look at the 2 p y, so the highest probability is going to be along the y-axis.

    最后我们来看一下,概率密度最高的是沿着y轴。

    麻省理工公开课 - 化学原理课程节选

  • I'm talking about four-week Treasury bills; 2.25% the Federal Funds Rate is still at 2.25% but at least the more prominent three-month T-bill rate is at the end.

    我在谈论月国库券;,联邦基金利率仍在%,但是至少显著地,季度国库券利率还在最低端。

    耶鲁公开课 - 金融市场课程节选

  • In the last week the Treasury bill rate on the United States four-week Treasury bill which is the standard 0.2% essentially three month it fell to 0.2%.

    上周,美国月国库券的,国库券利率,一般作为标准来看,本质上,在三个月内,跌落到。

    耶鲁公开课 - 金融市场课程节选

  • Good, so even if everyone in the number-- everyone in the room didn't choose randomly but they all chose a 100, a very unlikely circumstance, but even if everyone had chosen 100, the highest, the average, sorry, the highest two-thirds of the average could possibly be is 66 2/3, hence 67 would be a pretty good choice in that case.

    好的,如果每个人,教室里的每个人不是随机选择数字,而是全选了100,这好像不太可能,但如果每个人真的都选了100,就是最大的书,那平均数,抱歉,平均数的2/3会是66又2/3,此情况下67应该是个不错的选项

    耶鲁公开课 - 博弈论课程节选

  • So z equals 7 -- this is the cut-off where, in fact, the sigma orbital is going to be higher in energy than the pi 2 p orbitals.

    所以z等于7-这是分界点,实际上,sigma轨道能量,要比π2p轨道高。

    麻省理工公开课 - 化学原理课程节选

  • Let's multiply both sides by 2, I'll get 2q1* is equal to a - c over b - q1*.

    等式两边同时乘以2,得到,2q1*=/b-q1

    耶鲁公开课 - 博弈论课程节选

  • And then the number of pairs at month n is the number of pairs at month n - 1 plus the number of pairs at month n - 2.

    我们让第一个月的兔子数是1对,第n个月的兔子对数,是第n-1个月的兔子对数。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So, the higher the covariance is, generally, the higher--you can see from here-- 2 of the portfolio.

    所以总的来说,你可以从这里看出,协方差越大-,投资组合的σ2越高,the,higher,the,σ

    耶鲁公开课 - 金融市场课程节选

  • So what we can say is look at each of these separately, so if we start with looking at the 2 p z orbital, the highest probability of finding an electron in the 2 p z orbital, is going to be along this z-axis.

    我们可以来分别看看这些图,首先来看看2pz轨道,在2pz轨道里,找到电子的最大概率,是沿着z轴。

    麻省理工公开课 - 化学原理课程节选

  • What's that telling me is that if Player 2 chooses not to produce then Player 1's best response is a - c over 2b.

    参与人2产量为0而参与人1最佳对策是,/2b,这能说明什么

    耶鲁公开课 - 博弈论课程节选

  • The price of the two-period bond is 1/2 and the price of the one-period bond is 1/.

    所以两年期债券的价格是1/^2,一年期债券的价格则是1/

    耶鲁公开课 - 金融市场课程节选

  • So, that is not--your return is actually higher than 2.51% on an annualized basis.

    所以,你的实际年收益率,应该高于2.51%

    耶鲁公开课 - 金融市场课程节选

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