• R So let's get rid of R in this expression here.

    利用这个式子,我们就可以消去。

    麻省理工公开课 - 热力学与动力学课程节选

  • We know it's going around in a circle because if I find the length of this vector, which is the x-square part, plus the y-square part, I just get r square at all times, because sine square plus cosine square is one.

    我们之所以知道它做圆周运动,是因为我求出了这个矢量的模长,也就是 x 的平方加上 y 的平方,我就得到了它在任意时刻的模长平方,因为正弦平方加余弦平方始终等于1

    耶鲁公开课 - 基础物理课程节选

  • If you get them backwards, logr you will integrate one over r and will get log r.

    如果你逆推的话,对1/r积分得到。

    麻省理工公开课 - 固态化学导论课程节选

  • So we have the operationon the wave function in terms of r, theta, and phi and remember this e is just our binding energy for the electron, and we get back out this wave function.

    我们用r,θ,φ来表示,将算符作用于波函数,而且记住e仅仅是电子结合能,然后后面加上波函数。

    麻省理工公开课 - 化学原理课程节选

  • When you get one over R, you get a gradual fall.

    当你用1除以R,你得到逐渐的下降。

    麻省理工公开课 - 固态化学导论课程节选

  • If you get one over R squared, it'll be a little steeper.

    如果你用1除以R的平方,它会变得稍微陡峭一些。

    麻省理工公开课 - 固态化学导论课程节选

  • So, we can get from these energy differences to frequency h by frequency is equal to r sub h over Planck's constant 1 times 1 over n final squared minus 1 over n initial squared.

    所以我们通过不同能量,得到不同频率,频率等于R下标,除以普朗克常数乘以1除以n末的平方减去。

    麻省理工公开课 - 化学原理课程节选

  • So, the number of nuclei, 119 if we were to sit and count these as well, is 119. So, we'll multiply that by just pi, r squared, to get that cross-section, and divide all of that by 1 . 39 meters squared.

    如果你们数的话,原子核的数是,我们用它乘以πr的平方,得到横截面积,除以1。39平方米。

    麻省理工公开课 - 化学原理课程节选

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