J++ Now here's the semicolon, J less than N, where N is this, J plus, plus; so what am I doing?

现在这里是一个分号，J小于N，N是这个，那么我在做什么？

哈佛公开课 - 计算机科学课程节选

What I am going to do now is I am going to multiply by N Avogadro and then add Born repulsion.

我接下来要做的是,将其乘以阿伏加德罗常数,再加入Born的排斥作用。

麻省理工公开课 - 固态化学导论课程节选

And how about if the array is size N, and I say bracket N, where am I referring?

如果那个数组的大小为N，那会怎么样，我指明，涉及到了那个地方？

哈佛公开课 - 计算机科学课程节选

O Right there, order n. So I have order n operations at each level in the tree. And then how many levels deep am I? Well, that's the divide, right? So how many levels do I have?

在这儿,所以我在树的每个层次都要做O的操作,那个这棵有多少层呢？,这是一个除法，不是吗？

麻省理工公开课 - 计算机科学及编程导论课程节选

e The charge on the anion times minus e, so there is the minus e squared, 0R0 and divided by 4 pi epsilon zero r naught, because now I am evaluating this function at r naught, one minus one over n where n is the Born exponent.

阴离子的电荷乘以，因此会有-e的频繁，除以4πε,因为现在我用r圈评估这个函数，1-1/n，n是波恩指数。

麻省理工公开课 - 固态化学导论课程节选