J++ Now here's the semicolon, J less than N, where N is this, J plus, plus; so what am I doing?
现在这里是一个分号,J小于N,N是这个,那么我在做什么?
What I am going to do now is I am going to multiply by N Avogadro and then add Born repulsion.
我接下来要做的是,将其乘以阿伏加德罗常数,再加入Born的排斥作用。
O Right there, order n. So I have order n operations at each level in the tree. And then how many levels deep am I? Well, that's the divide, right? So how many levels do I have?
在这儿,所以我在树的每个层次都要做O的操作,那个这棵有多少层呢?,这是一个除法,不是吗?
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