• The basic idea is, you take a guess and you -- whoops -- and you find the tangent of that guess.

    首先取猜想,然后,嗯,去取猜想那儿的切线。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Let's say you have to go through three or four operations to get a final number, well, do it algebraically.

    让我们说,你不得不通过3-4操作,才能得到最终的,好吧,用代方法求解。

    麻省理工公开课 - 固态化学导论课程节选

  • And frankly it would be incredibly time-consuming and tedious for me, to count this room full of people old school style-- 1, 2, 3 and so forth.

    坦白说,按学校的老办法一人一人的,1,2,3……,对我来说极其费时费力。

    哈佛公开课 - 计算机科学课程节选

  • I once counted the number of times he used the word the letter--O--in that poem, and I quit counting.

    我曾经过他到底在诗里用了多少"啊",最后我放弃了

    耶鲁公开课 - 美国内战与重建课程节选

  • So we have a total of 2, 4, 6, 8, 10 valence electrons, so I'll make sure I count to 10 as we fill up our molecular orbitals here.

    我们一共有2,4,6,8,10价电子,所以我一边填一边要确认,我到10。

    麻省理工公开课 - 化学原理课程节选

  • What's the biggest number you can represent with three decimal digits? Pardon?

    你们想用这3十进制表示什么?,请再说一遍?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • This adds on several hours to my work week.

    这给我增加了数个小时的工作时间。

    普林斯顿公开课 - 人性课程节选

  • Claire Elise is going to get her own vote plus 1, 2, 3, 4, 5, 6, 7, 8, 8 votes and Beatrice is getting 1, 2, 3, 4, 5, 6, 7, how did I end up with eight, I thought I had an odd number. 1, 2, 3, 4, 5, 6, 7 there must have been an odd number before.

    克莱尔·伊莉斯将获得自己的选票加上,12345678 8张选票,而比阿特丽斯获得1234567,我怎么出8来的,我想应该是,1234567,之前也应该是

    耶鲁公开课 - 博弈论课程节选

  • The Republic is also a utopia, a word that Plato does not use, was not coined until many, many centuries later by Sir Thomas More.

    理想国》也是乌托邦,一柏拉图不使用的词汇,直到数个世纪之后,才由Sir,Thomas,More,杜撰出来。

    耶鲁公开课 - 政治哲学导论课程节选

  • Yeah. So we have two orbitals, or four electrons that can have that set of quantum numbers.

    嗯,有我们有两轨道,也就是4电子可以有这套量子

    麻省理工公开课 - 化学原理课程节选

  • So now we're just counting up our orbitals, an orbital is completely described by the 3 quantum numbers.

    所以现在我们只要把这些轨道加起来,一轨道是由3量子完全确定的。

    麻省理工公开课 - 化学原理课程节选

  • Well, if intuitively the problem is the result of dividing an int by an int, surely a solution is: "Don't do that," right?

    好的,直观地看,如果那问题的原因是因为整型除以整型的话,无疑有解决方案是:“不要那样做“,是吗?

    哈佛公开课 - 计算机科学课程节选

  • So carbon 12. We know that it has the proton number, by definition, is 6. And the neutron number, 6 from 12 is 6. So it has 6 protons and 6 neutrons.

    所以碳12,我们知道它有质子,根据定义,那就是6,而电子,12减6等于6,所以它有6中子。

    麻省理工公开课 - 固态化学导论课程节选

  • Well, I could look at the value here, and compare it to the value I'm trying to find, and say the following; if the value I'm looking for is bigger than this value, where do I need to look? Just here.

    然后把它和目标比较,然后做出如下的判断:,如果目标值大于这值;,那么我应该去哪找呢?对,应该在这里,对不对?不可能在那儿。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Two significant digits is good enough.

    有效应该绰绰有余了。

    麻省理工公开课 - 固态化学导论课程节选

  • Is this a real or a float?

    看看到底是还是浮点

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So let's go to a second clicker question here and try one more. So why don't you tell me how many possible orbitals you can have in a single atom that have the following two quantum numbers?

    让我们来看下一道题目,你们来告诉我,有多少可能的轨道,含有这些量子呢?

    麻省理工公开课 - 化学原理课程节选

  • All right, so hopefully if you see any other combination of quantum numbers, for example, if it doesn't quickly come to you how many orbitals you have, you can actually try to write out all the possible orbitals and that should get you started.

    所以希望你们如果遇到,任何其它的量子组合的问题,如果你们不能马上想到有多少轨道,可以试着先写出所有的轨道,这是不错的切入点。

    麻省理工公开课 - 化学原理课程节选

  • - We know from Wednesday if -- briefly -- that there's this thing called a "char" or "char," depending on how you want to pronounce it, which is just a single character but where there's also an int.

    我们知道从周三起--简单说下-,我们有叫做“char“或“char“,看你们怎么读它了,那代表一单一的字符,但那里会有整型与之对应。

    哈佛公开课 - 计算机科学课程节选

  • So similarly, as we now move up only one more atom in the table, 3 so to an atomic number of three or lithium, now we're going from six variables all the way to nine variables.

    类似地就像我们现在,移动到周期表中仅仅多一电子的情况,移动到一原子为,或者锂元素,现在我们从6变量到了9变量。

    麻省理工公开课 - 化学原理课程节选

  • And I just want to point out that now we have these three quantum numbers.

    我想指出的是,现在我们有了,这3量子

    麻省理工公开课 - 化学原理课程节选

  • And we also, when we solved or we looked at the solution to that Schrodinger equation, what we saw was that we actually needed three different quantum numbers to fully describe the wave function of a hydrogen atom or to fully describe an orbital.

    此外,当我们解波函,或者考虑薛定谔方程的结果时,我们看到的确3不同的量子,完全刻画了氢原子,的波函或者说轨道。

    麻省理工公开课 - 化学原理课程节选

  • So, those are our three quantum numbers.

    这就是,3量子

    麻省理工公开课 - 化学原理课程节选

  • So we can completely describe an orbital with just using three quantum numbers, but we have this fourth quantum number that describes something about the electron that's required for now a complete description of the electron, and that's the idea of spin.

    所以我们可以用3,量子完全刻画轨道,但我们有这第四量子,来完整的,描述电子,这就是自旋的概念。

    麻省理工公开课 - 化学原理课程节选

  • And I said I'm giving you three decimal digits.

    我说给你们310进制

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • And then the number of pairs at month n is the number of pairs at month n - 1 plus the number of pairs at month n - 2.

    我们让第一月的兔子是1对,第n月的兔子对,是第n-1月的兔子对

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • m And the third one is called m, l it's also m sub l.

    第三量子叫做,也叫做m小标。

    麻省理工公开课 - 化学原理课程节选

  • The reason there are three quantum numbers is we're describing an orbital in three dimensions, so it makes sense that we would need to describe in terms of three different quantum numbers.

    我们需要,3量子的原因,是因为我们描述的是一,三维的轨道,所以我们需要,3不同的量子,来描述它。

    麻省理工公开课 - 化学原理课程节选

  • How many different orbitals can you have that have those two quantum numbers in them?

    有多少轨道是,含有这两量子的?

    麻省理工公开课 - 化学原理课程节选

  • So what do you do when you're a kid and you want 3 to count a little faster than 1 and 2 and 3 and 4 what is the simplest thing you do?

    因此当你还是孩子的时候,你想得比1,2,3,4快一些3,最简单的方法是什么?

    哈佛公开课 - 计算机科学课程节选

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