• Node types are returned as integers, and allow you to handle each node appropriately; an element (type 1) has a name, but no value, whereas a text node (type 3) has a value but no name.

    节点类型以整数返回,并且允许您适当地处理每一个节点;一个元素(类型1)有名称没有值,但是一个文本节点(类型3)有值没有名称。

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  • The title of each paragraph can be imagined to be the heading nodes under the root node (level 1).

    每一个段落的名字可以被想象为根节点下的标题节点(层次1)。

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  • Look back at Figure 1, and imagine each node is a person and each diagram is a team design.

    请回顾图1,想象一下每一个结点就是一个人,每一个图表就是一个团队设计。

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  • A property of this node is its unique identifier — a 1 to 12 character label.

    此结点有一个属性,即它的唯一标识符——由1到12个字符组成的标签。

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  • Now node 1 has two partial sums.

    现在节点1有两个部分和了。

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  • For each element in such a pattern, a -1 or + 1, there is a node object in an array of nodes.

    对应于这类图案中的每一个元素,- 1或者+ 1,在节点数组中都有一个节点对象。

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  • As illustrated in Figure 1, each node is connected to two networks.

    如图1所示,每个节点均连接至两个网络。

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  • In this case, processor 0 is attached to logical node 0, processor 1 to node 1, and so on.

    本例中,处理器0将附属于逻辑节点0,处理器1附属于节点1,以此类推。

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  • Throughput scaling from 2 adapters/1 node to 4 adapters/2 nodes was computed for each send message size.

    对于每种消息大小,分别计算从2 个适配器/1 个节点到4 个适配器/2 个节点的吞吐量变化。

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  • Node 2 sends its integer to node 1, and node 4 sends its integer to node 3.

    节点2将自己的整数发送给节点1,节点4将自己的整数发送给节点3。

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  • From the new cluster node Menu, type "1" to create a new cluster.

    从新集群节点菜单,键入“1 ”创建新的集群。

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  • One time, you may be directed to node 1. Another time, you may be directed to node 2, and so on.

    一次可能转发到节点1,而另一次可能转发到节点2,等等。

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  • In Figure 1, the state machine starts at node 1.

    在图1中,状态机从节点1开始。

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  • As a result, we just used yum to pull it down and perform the installation on an edge node [1].

    因此,我们只是使用yum把它拉下来,然后在edge节点[1]上执行安装操作。

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  • where d(n) for a hidden node n, turns on (1) how much n influences any given output node; and (2) how much that output node itself influences the overall error of the net.

    其中d(n)是隐藏节点 n 的函数,让我们来看(1)n对任何给出的输出节点有多大影响;(2)输出节点本身对网络整体的误差有多少影响。

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  • This node is connected to Task 1, symbolized by a yellow rectangle with rounded corners.

    此节点连接到Task1,后者用黄色的圆角矩形表示。

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  • Method 1: Set up the backup node.

    方法1:设置备份节点。

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  • The rope counterpart simply creates a new concatenation node, which is an o (1) operation.

    rope版本的连接操作则只是创建一个新的连接节点,这是个o(1)操作。

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  • Table 1 illustrates a node named abcdefgh00 with five host names.

    表1说明了一个名为abcdefgh00的节点具有五个主机名。

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  • Finally, notice the last child node of the departments node in Figure 1.

    最后,注意图1中departments节点的最后一个子节点。

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  • For the document in Listing 1, PRODUCTS is the root node.

    对于清单1中的文档,PRODUCTS是根节点。

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  • In Figure 1, the name of the root node is org.

    在图1中,根节点的名称为org。

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  • In the present implementation at least, if this sum is less than zero, the net sets the node to -1, and if it is greater than or equal to zero, the net sets the node to + 1.

    至少在当前的实现中,如果这个和小于0,网络就将节点设置为- 1,如果它大于或等于0,则网络将节点的值设置为+ 1。

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  • Then you can define the master replicate using -m option to specify the master node as g_pkcdr.1.

    然后可以使用- m选项定义主复制,将主节点指定为g_pkcdr . 1。

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  • Install WebSphere Application Server base on the node ha3 (steps 1-9 above, only) with the following information.

    在节点ha3上根据如下信息安装WebSphereApplicationServer中心(只需进行步骤1 - 9)。

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  • The dijit.tree.ForestStoreModel in Listing 1 connects a root node with multiple root items in a diji.tree.

    清单1 中的 dijit.tree.ForestStoreModel 将一个根节点和diji.tree 中的多个根条目连接起来。

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  • Yup, so one total node, 2 minus 1 is 1, and that means since l is equal to 1, we have one angular nodes, and that leaves us with how many radial nodes?

    一个节点,2减去1等于1,因为l等于1,我们有一个角向节点,那剩下径向节点有多少个呢?

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  • On node 1, the cluster members named clus1_1 and clus1_2 are an example of horizontal clustering on one node.

    在节点1上,集群成员clus1_1与clus1_2是该节点上水平集群化的例子。

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  • In this simple configuration, all nodes simply reside on the same node (see Figure 1).

    在这个简单的配置中,所有节点都驻留在同一个主机上(见图1)。

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  • Node 1 adds these partial sums to get the final sum.

    节点1对这些部分和进行求和,从而得出最终的总和。

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