The signed division will take more time to execute because it rounds towards zero, while a shift rounds towards minus infinity.
有符号的除法要耗费更多的时间，因为除法是使最终结果趋向于零的，而移位则是趋向于负无穷。
We have the integral from minus infinity to plus infinity of F(x)*x*dx, and that's really--you see it's the same thing because an integral is analogous to a summation.
我们用从负无穷到正无穷的积分公式F(x)*x*dx,你看到的，这是相同的事，因为积分是类似的求和过程。
This is minus one over r, so I get m MG over r with a minus sign, and that has to be evaluated between infinity and capital R.
这是r的负值，所以在mMG/r上加-号，它处于,无穷远和R之间。
This is minus one over r, so I get m MG over r with a minus sign, and that has to be evaluated between infinity and capital R.
这是r的负值，所以在mMG/r上加-号，它处于,无穷远和R之间。
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