The signed division will take more time to execute because it rounds towards zero, while a shift rounds towards minus infinity.
有符号的除法要耗费更多的时间,因为除法是使最终结果趋向于零的,而移位则是趋向于负无穷。
We have the integral from minus infinity to plus infinity of F(x)*x*dx, and that's really--you see it's the same thing because an integral is analogous to a summation.
我们用从负无穷到正无穷的积分公式F(x)*x*dx,你看到的,这是相同的事,因为积分是类似的求和过程。
If I had taken as my interpolation scheme, my white curve here, I could go to infinity and have the equivalent of absolute zero being at infinity, minus infinity.
要注意,如果我们采用,像图中白线这样的插值方案的话,我就可以一直降温下去,相应的绝对零度点。
Well, the energy at infinity is zero -K and the energy in the ground state is minus K.
无限远处的能量值为,而基态能量值为。
The ionization energy must then be nothing more than, that is the energy to go from the ground state here to n equals infinity, so that would be the energy at state infinity minus the energy of the ground state.
这个电离能一定不会大于,从基态到n为无限大时的能量,而是等于,无限远处的能量减去基态能量。
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