Let's go back to that triangle; seen from above there's three equal nodes.
我们回到那个三角形：从上往下，你看能到三个平等的节点。
These B nodes are equal, but they are not the same node.
这两个 B节点是等同的，但它们不是相同的节点。
For example, if you create two empty element nodes named "foo" without any attributes, they are equal, even though they are not identical.
例如，如果创建了两个没有任何属性的、名为“foo”的空元素节点，那么它们是相等的，但是它们不是相同的。
Yup, so one total node, 2 minus 1 is 1, and that means since l is equal to 1, we have one angular nodes, and that leaves us with how many radial nodes?
一个节点，2减去1等于1,因为l等于1,我们有一个角向节点，那剩下径向节点有多少个呢？
But two nodes that are equal are not necessarily the same.
但是两个相等的节点不一定是相同的。
And when we talk about angular nodes, the number of angular nodes we have in an orbital is going to be equal to l.
当我们谈到角向节点时，一个轨道的，角向节点数等于l。
We started with eight nodes equal in all respects except their fitness values.
我们以八个节点为起始，他们除了适合值不同外其他各个方面均相同。
Because of the similarity of these sub-elements, the coefficients of stiffness for the nodes of the same zone (material) are equal in the whole stiffness field of the structure.
由于子元间的相似性，结构的整体劲度场中同一类型的结点，其劲度系数是相同的。
Compares the current expression and child nodes to another expression to determine whether they are equal.
将目前的运算式和子节点与其他运算式比较，判断它们是否相等。
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
题目大意： 给定两个二叉树，判断两者是否是相同的二叉树。 即结构相同且对应节点的值也相同。
New calculating method of nodes based on arc approaching lnvolute with equal errors;
通过设置一个阈值，算法可以检测曲率较大的特征点，用于圆弧逼近匹配。
New calculating method of nodes based on arc approaching lnvolute with equal errors;
通过设置一个阈值，算法可以检测曲率较大的特征点，用于圆弧逼近匹配。
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