• Medium instance (c1.medium).

    中等实例(c1 . medium)。

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  • Extra large instance (c1.xlarge).

    超大实例(c1 .xlarge)。

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  • The cluster is named c1.

    集群名为c1。

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  • On c1, how do I evaluate my integral?

    那么怎么在c1上计算积分?

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  • C1 be the right-most character of s1.

    C1是S1最右侧的字符。

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  • Last, I execute C1 again along with C2.

    最后,我再次执行c1和C2。

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  • Present value(PV) = discount factor * C1

    现值(PV)=贴现因子 *C1

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  • At least one reference held within collection c1.

    集合c1中至少有一个引用。

    youdao

  • I had to know C1, which I calculated; I measured it.

    我们要知道C1值,我已经测好了。

    youdao

  • C1 pedicle screws are stiffer than C1 lateral mass screws.

    颈1椎弓根固定较侧块固定更稳定。

    youdao

  • The name of the cursor, C1 in the sample, can be freely chosen.

    可以自由选择游标的名称,在此示例中使用C1。

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  • Assume there is an index T1X on (c2, c1) columns of a table T1.

    假设在表t 1的(c 2,c1)列上有一个索引t1x。

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  • I get that the line integral on c1 — Well, a lot of stuff goes away.

    得到c1上的线积分,大部分就消去了。

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  • OK, so I proved that my two line integrals along C1 and C2 are equal.

    我证出了分别沿着C1和C2的两个线积分是相等的。

    youdao

  • The free connection pool now contains two free connections - c1 and c2.

    空闲连接池现在包含两个空闲连接:c1和c2。

    youdao

  • The connection it was using, c1, is put back into the free connection pool.

    它使用的连接c1将被放回空闲连接池。

    youdao

  • C2 C1 and C2, well, I observe that if I do C1 minus C2, I get a closed path.

    路径C1和C2,如果我组合C1和,就得到闭合路径。

    youdao

  • It finds c1 in the free connection pool, and checks how long ago it was created.

    它在空闲连接池中找到c1,并检查它创建了多长时间。

    youdao

  • where runstats (no distribution) would provide us the following information for C1

    runstats(无分布)将提供关于 C1 的以下信息

    youdao

  • Consider a software component (C1) that is part of a software architecture of a system.

    请考虑一个属于某个系统的软件架构组成部分的软件组件(C1)。

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  • By this time, c1 has been in the free connection pool for 6 minutes, and c2 for 3 minutes.

    到此时为止,c1已在空闲连接池中存在了6分钟,c2存在了3分钟。

    youdao

  • Relationship Between Screw Trajectory of C1 Lateral Mass Screw and Internal Carotid Artery.

    C1侧块螺钉通道和颈内动脉之间的关系。

    youdao

  • In contrast, a search on -content integration + rulebased: : c1 returned about 9,000 results.

    相反,搜索- contentintegration +rulebased:c1时就返回了大约9,000个结果。

    youdao

  • Consider the simple example of two statements targeted for table T1 - CREATE table T1 (C1 INT).

    考虑一个简单的例子,例子中有两个以表t 1为目标的语句——CREATETABLET1 (C1INT)。

    youdao

  • While class C1 may be defined originally in ontology O1, it can be extended in other ontologies.

    类C1本来是由本体O1定义出来的,然而,它也可以是由其他的本体扩展出来的。

    youdao

  • The Web application allows two use cases: one starting from page b1 and one starting from page c1.

    该Web应用程序允许两个用例:一种是从页面b1开始,一种是从页面c1 开始。

    youdao

  • In this case, the code has actually specified all the members of cluster c1 where the EJB is residing.

    在本例中,代码实际上已经指定了EJB所在的集群c1的所有成员。

    youdao

  • (the following example USES down-level client c1, V8.2 client c2 and V8.2 server s1 to illustrate the scenario).

    (下面的例子使用未升级的客户机c 1、V8.2客户机c2和V8.2服务器s1来解释该场景)。

    youdao

  • Since the pool contains two connections, and Minimum connections is set to 1, the connection Manager closes c1.

    由于池包含两个连接,并且最小连接设置为1,所以ConnectionManager将关闭c1。

    youdao

  • What is odd is that, according to the plan, the next iteration would be C1, the first iteration of Construction.

    奇怪的是,根据计划,下一次迭代是C1,构建的第一次迭代。

    youdao

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