But then, I combine i times Ax with i times Bx, because that's the vector parallel to i, with the length Ax.
然后我把 i ? Ax 和 i ? Bx 加起来,因为这是平行于 i,模长为 Ax 的矢量
All of the businesses are in Madison Avenue, one block away, parallel.
商业机构都在隔这儿一个街区的麦迪逊大道,它跟这条街是平行的。
This part, being parallel to i, has to be a multiple of i.
平行于 i 的这部分必然是 i 的倍数
That's clear. If I add them, I'll get a vector parallel to i with lengths Ax + Bx.
这很明显 如果把他们加起来,就得到一个平行于 i,模长为 Ax + Bx 的矢量
This part, being parallel to j, has to be some multiple of j.
而平行于 j 的那部分,也必然是 j 的倍数
That's the vector parallel to i, with length Bx.
这个是平行于 i,模长为 Bx 的矢量
Then j with Ay + By.
同样有平行于 j,模长为 Ay + By 的矢量
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