You get 2.18 times 10 to the plus 6 meters per second, 1% which is about 1% of the value of the speed of light.
。18*10^6米每秒,得到的速度大概是光速的。
And in order to get into college, you need at least 2.0.
而要想进入大学,至少需要2.0。
Then you get to 2 and 3 John, two letters that are written to "the elected lady and her children."
然后是约翰二书和约翰三书,这两封信都是写给,“蒙拣选的太太和他的儿女“
And for a 2 s orbital, you get a graph that's going to look something like this.
对于2s轨道,你们可以得到一个大致是这样的图。
If you multiply it by 2, you get a vector two times as long.
如果拿它乘以2,你就得到一个两倍长的矢量
But you'll see that very clearly that Steven's right: that choosing 2 will always get me 5% more of the votes than choosing 1 from here on down.
你会发现斯蒂文说的很对,从这里开始,选立场2总会比,选立场1多获得5%选票
I going to come back in a second to how it actually does that, but it basically says, get me x value for p 1, get me the x value for p 2, compare them, just as you would normally.
是一个类的实例,我要去取的这个实例,所关联的x值,我稍后会讲讲实际上,这里是怎么实现的,但是基本上它的意思就是,给我p1的x值。
How many times you can divide N by 2 before you get down to 1?
在得到1之前需要将N除以2做几次呢?
So if you put 1 and 2 together you can get only changing things could be destroyed.
把1和2放在一块儿就可以得出,只有能改变的东西能毁灭。
it's also important how much you get, like 2:1 or first.
同样重要的是你的成绩如何,是2:1还是第一。
He saw that if you take the atomic mass of chlorine, 2 add it to the atomic mass of iodine, divide by two, you get something that is really close to the atomic mass of bromine.
他看到,如果你将氯的原子质量,加上碘的原子质量,除以,得到的数将与,溴的原子质量很接近。
If you start with only one, you have two pieces of DNA, then you'll get 2 to the Nth fragments after N cycles because each cycle you're doubling the number.
如果你从仅仅一个DNA开始,你有两条DNA链,经过N次循环后,就得到二的N次方个DNA片段,因为每次循环都使其数量翻倍
You might be asking where the 2 p z orbital is and we'll get to that soon once we need it.
你可能会问2pz轨道在哪里,我们等会就会讲到这个问题。
So, in particular, let's start working out what share of the votes you'd get if you chose position 1 or position 2, against different positions the other guy can choose.
先来看看如果你选择立场1和2,在你对手选择不同立场时,你分别能获得多少选票
Let's just... We'll get there, just to remind you, the way we read this is you give me a quantity of Firm 2, I find Firm 1's best response by going across to the pink line and dropping down.
我们当然也能算出来,提醒一下各位,这个图像的个意思是任意给出公司2产量,然后通过这条粉色的线,就可找出与之对应的公司1的最佳对策
If you substitute it all in, you get basically order 2 to the n.
得到的是2的n次方个基本问题,指数级的,这是个问题,好。
You add the two, you get 10 = 5a and you get a = 2.
把两个方程相加,你就会得到 10 = 5a 算出 a = 2
So essentially, each of these orbitals come from linear combinations of all of the original orbitals, and it's hard to picture exactly how that happens, but one that you can at least start to get an idea is if you think about combining the 2 s and the 2 p z here, which is not quite accurate because of course, we're combining all of them.
本质上,这些轨道每个都来,自原来所有轨道的线性组合,我们很难想象这是怎么发生的,但你们可以至少有个概念,如果你们考虑2s和2pz轨道的结合,这当然是不太准确的,因为我们要把所有的都组合起来。
You can take a derivative of the derivative and you can get the acceleration vector, will be d^2r over dt^2, and you can also write it as dv over dt.
你可以对导数再求一次导,你就可以得到加速度矢量,也就是 d^2 r / dt^2,你也可以写成 dv / dt
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