Map和grep对列表的每个元素计算块或表达式。
Map and grep evaluate a block or an expression for each element of a list.
最后继承了内联显示属性但计算块。这可能是怎么做的?
Last inherited display property is inline but computed is block. How is this even possible?
采用滑动时间窗口生成块运动方向时间序列,在此时间序列的基础上计算块的累积量和主运动方向。
And a time sequence of motion orientation for each block is generated over a sliding time window. Then accumulation and main motion orientation are computed according to the sequence.
Anything that tells him to sense something like the user's mouse or the edge of his screen is actually purple in color; and so they're nicely colorized and all this but the one that's adventurous right now is this.
能够让计算机感知鼠标或屏幕边缘的图块,都是紫色的;,这些图块五颜六色,但这里有一个不太靠谱的按键。
So on the left hand side of this particular languages environment I have some puzzle pieces and they are shaped and colored ; in a manner that hints out their functionality; any blocks that tell the Cat as we'll see in a moment, what to do something happen to be orange.
在这个程序语言界面的左手边有一些拼图,他们的形状和颜色代表他们的功能,我们马上就能看到;,任何一个给计算机发出指令的图块,都是橙色的。
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