And then from that start point, get the x-value. Same thing, from that instance, get the endpoint, from that end point get the x-value, square.

取得结束点，然后取得结束点的y坐标，然后求差开平方，然后同样求的y坐标。

麻省理工公开课 - 计算机科学及编程导论课程节选

Well, maybe this ended up at location 7, 8, 7 8 9 9 so what's really in x is the number 7, 8, 9, which is the address in memory, but again, uninteresting.

嗯，可能这个在地址7，8，9结束，那么在x中实际上是数字，那是内存中的地址，但是，那是没有什么用的。

哈佛公开课 - 计算机科学课程节选

Now, I prefaced this a few minutes ago about saying Professor Guttag wasn't going to like me.

结束点返回x坐标,然后把它们加起来。

麻省理工公开课 - 计算机科学及编程导论课程节选