Now. You might look at that and say, well that's just a lot like what we had over here Right? We had some additive constant plus a simpler version of the same problem reduced in size by 1.
现在你可能会看着这个说,这很像我们以前做过的,对不对?我们用一些附加的常量,加上问题的另外一个规模缩小了1的,简化版本来代替这个问题本身。
So, in this program when we call this version of swap 1 and 2 do not end up here, right?
所以,在这个程序中,当我们调用这个swap版本1,和版本2,不是在这里结束,对不?
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