基本上，只要当一个方法的最后一个参数是一个对象数组，或者是一个有三个点的参数，你就可以向这个方法传入多重参数。

Basically, whenever the last argument of a method is an array of objects, or a parameter declaration with a triple dot, you can pass multiple parameters to this method.

youdao

不过，我们在这里构造的字节数组并不是很正确，我们将在下一节看到这一点。

However, the byte arrays we've constructed here aren't quite right, as we'll see in the next section.

youdao

为了展示这一点，假设您有两个双精度的数组 a 和 b，并且要创建第三个数组 x，比如 x=a+b。

To illustrate this, suppose you have two double arrays a and b and want to create a third array x such that x=a+b.

youdao

It says, well I'm going to print out first and last just so you can see it, and then I say, gee 2 if last minus first is less than 2, that is, if there's no more than two elements left in the list, then I can just check those two elements and return the answer.

然后它计算了尾点和开始点的差,如果小于2的话,也就是说数组中的元素小于等于，我对这两个元素进行比较,然后返回结果就可以了，否则的话，我们就去寻找中值点，注意它是怎么实现的,首先这个指向一个列表的开头。

麻省理工公开课 - 计算机科学及编程导论课程节选

So this first little piece of code right here says, ok you give me 2 points, I'll create another 1 of these lists and I'll simply take the x, sorry I shouldn't say x, I'm going to assume it's the x, the x-values are the two points, add them together, just right there, the y-values, add them together and return that list.

好，为了来认识到这一点,让我们来看一个简单的小例子，在你们的课堂手册上，你可以看到我写了一个小程序,它假设我得到了，这些点中的一些，我想对它们做一些操作，例如我想把它们加到一起，那么这里的第一小片，代码的意思是，好给我两个点，我会再创建一个数组。

麻省理工公开课 - 计算机科学及编程导论课程节选

And I keep cutting the problem down.

那么我应该选取数组中的哪个点呢？

麻省理工公开课 - 计算机科学及编程导论课程节选