括号运算
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... brachistochrone problem 最速降线问题 brachistochrone 最速降线 bracket operation 括号运算 ...
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括号运算式 bracket expression
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bracket operation - 引用次数：5
In section 1.1. we define the mapping a on circle in double quiver Q of a quiver Q, and give a strict defition of bracket operation in Lie algebra,then prove it is a Lie bracket.
在1．1节中，我们定义了箭图Q的重箭图（?） 循环上的映射σ，用它给出了项链李代数括号运算的一个严格定义，并用此定义证明了这是一个李运算。
参考来源 - 项链李代数的结构与性质
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双语例句原声例句
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方括号运算符用来检索数组和集合的元素。
The bracket operator is used to retrieve elements of arrays and collections.
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和字符串不同的是，列表是可以修改的。方括号运算符放到一个赋值语句的等号左侧的时候，就会把对应位置的列表元素重新赋值。
Unlike strings, lists are mutable. When the bracket operator appears on the left side of an assignment, it identifies the element of the list that will be assigned.
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注意，最初的 “最小字符数” 子模式和运算符子模式都在捕捉圆括号内进行了指定：\(...\)。
Note that both the initial "minimal number of characters" subpattern and the operator subpattern are specified within capturing parentheses: \(...\).
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I just want to make mention of this in case there's ever doubt, generally parentheses do solve your problem as an arithmetic but do realize this is some lower level details we'll come back to over time.
是想告诉大家如果你对某些式子的前后运算关系不确定，就加上括号,这都是一些小细节,我们以后还是会再提到的。
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