对于2s轨道,它等于6倍的a0。
And it turns out that for a 2 s orbital, that's equal to 6 times a nought.
它等于质子数,加上中子数。
And it is equal to the sum of the number of protons plus the number of neutrons.
对于3s轨道,它等于11.5 a0。
And in the case of the 3 s orbital, that's going to be equal to 11. 5 times a nought.
If this were to be an absolute zero Kelvin, then we could we can have something, T2 Sorry, it's T2.
如果它等于绝对零度,我们可以,对不起,这是。
And in the case of the 3 s orbital, that's going to be equal to 11 . 5 times a nought.
对于3s轨道,它等于11.5a0.
So I could have written right here immediately CvdT equals Cv dT, and that was the end of my derivation.
于是我在这里就可以直接写,来它等于,完成了整个推导。
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