Let's suppose X knows what Y is doing.
假设X知道Y正在干什么。
然后打印y是什么。
Well, what is this distance? It is just y,or maybe absolute value of y.
这里的距离是什么?是y,准确地说是y的绝对值。
What is y-y0? The final y is 0, the initial y is 15. You solve for that equation and you will find the final velocity.
-y0是什么,末态的y是0,初态的y是15 你们已经得到,然后你可以找到最终速度
If its in Cartesian form I'll pass in an x and y and compute what a radius and angle is.
来得到的这个点,我都可以得到这个点的,全部的这种信息。
So, what we end up having is three of these pi -- 2 p y 2 p y bonds, we can have one between these two carbons here.
我们剩下的有三个π键-,2py2py键,在这两个碳原子之间会有一个。
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