So, speed, which is the scalar quantity is going to be just the magnitude of the vector, V.

因此，速度的大小即是,矢量V的模长。

youdao

But now notice, I can substitute now for this v squared, I can substitute the square of this that is the orbital speed and then I get M G over R.

现在注意我能,代替这个v平方，我能代入这个平方,那是轨道速度,然后得到MG在R上。

youdao

Out pops that speed with which you can escape the gravitational pull of capital M, which is the V square root of two times larger than this V.

逃离M的重力,所需的速度为,√2乘以,比逃逸速度小的。

youdao

If you want to find the speed there, you put the equation v^=v0^-2g.

如果你想求出那一点的速度,可利用方程v^=v0^-2g

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