The IntegrateInt process also writes the integer 0 (which is, after all, the current value of the running total) onto channel b.

IntegrateInt进程也把整数0(是当前汇总的值)写入通道b。

youdao

This makes the IntegrateInt process update the running total to 1 (the previous total) + 2 (the new value) = 3 and write this integer out onto channel b.

这使 IntegrateInt 进程把汇总值更新为 1 （前一个汇总值） + 2 （新值） = 3 并把这个整数写入通道 b。

youdao

This causes the IntegrateInt process to change the running total to 0+1=1 and thereby write the integer 1 onto channel b.

这造成 IntegrateInt 进程把汇总值修改成 0+1=1，所以把整数 1 写入通道 b。

youdao