If I look for, say, minus 1, you might go, gee, wait a minute, if I was just doing linear search, I would've known right away that minus one wasn't in this list, because it's sorted and it's smaller than the first elements.
如果我要查找-1,你可能要怒了,呵呵,等一等,如果我用的是线性查找,我不会知道-1不在这个列表中,但是列表是排好序的,1又比第一个元素小。
du/dV So now our du/dV, dp/dT at constant T is just T times dp/dT which is just p over T minus p, it's zero.
现在我们的恒定温度下的,等于T乘以dp/dT,在这里,等于p除以T,最后再减去p,结果是0。
So this is 3, plus 2 times 3, plus 4 t minus 2.
也就是3+2*3+4t,好。
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