Same sort of subtraction problem, what do we have for the ionization energy of the 2 s electron?
进行类似的减法运算,得到的,2,s,电子的电离能应该是多大呢?
So let's think about the energy required now to remove a 2 s electron, let's say we're removing it from boron plus 1 versus neutral boron.
那么让我们来想一想,拿走一个,2,s,电子所消耗的能量,假设一个是从正一价硼离子中拿走1,另一个是从中性硼原子中拿走。
A laser pulse can modify the electron s state so that it has the density distribution shown in green.
一束激光脉冲可以改变电子的状态,使得其有了图中绿色显示的密度分布。
So, the size still for an s orbital is larger than for a d orbital, but what we say is that an s electron can actually penetrate closer to the nucleus.
轨道的尺寸比,p轨道还是要大,但我们说的是s轨道可以,穿透到更接近原子核的地方。
And we know that it's electron density between the nuclei that holds two atoms together in a bond.
我们知道是两个原子核之间的,电子密度保持两个原子在一起成键的。
So this tells you that it's electron structure that governs.
这告诉你们,都是电子结构在支配。
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