Axial motion and misalignment (radial and angular offset) between the encoder shaft and the drive shaft are compensated by the coupling.

轴向运动和编码器之间的轴和驱动轴偏差(径向和角向偏移)进行补偿的耦合。

youdao

Yup, so one total node, 2 minus 1 is 1, and that means since l is equal to 1, we have one angular nodes, and that leaves us with how many radial nodes?

一个节点，2减去1等于1,因为l等于1,我们有一个角向节点，那剩下径向节点有多少个呢？

youdao

So, remember we can break up the total wave function into the radial part and the angular part.

记住我们可以把整体波函数，分解成径向部分和角向部分。

youdao

so, remember we can break up the total wave function into the radial part and the angular part.

记住我们可以把整体波函数,分解成径向部分和角向部分。

麻省理工公开课 - 化学原理课程节选

Yup, so one total node, 2 minus 1 is 1, and that means since l is equal to 1, we have one angular nodes, and that leaves us with how many radial nodes?

一个节点，２减去１等于１,因为ｌ等于１,我们有一个角向节点，那剩下径向节点有多少个呢？

麻省理工公开课 - 化学原理课程节选

So you can see there's this radial part here, and you have the angular part, you can combine the two parts to get the total wave function.

你们可以看到，这是径向部分，这是角向部分，把这两部分结合到一起,就是总的波函数。

麻省理工公开课 - 化学原理课程节选