In the absence of synchronization, if one thread writes to a variable and another thread reads that same variable, the reading thread could see stale, or out-of-date, data.
没有同步时，如果一个线程读取另外一个线程正在写的变量，读的线程将看到过时的数据。
As a result, some native code in the current stack frame is now out of date, that is, stale.
结果，当前堆栈帧中的某些本机代码是过时的、陈旧的。
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