... 东莨菪亭 scopoletin 诣零环 nil ring 非线性规划问题 non linear programming problem ...
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nil commutative ring 诣零交换环
near nil semisimple ring 近似诣零半单环
nil radical of near-ring 拟环的诣零根
generalized nil radical of ring 环的广义诣零根
This peper gives two necessary and sufficient conditions for a ring to be a nil MHR-ring. It is obtained that any nil MHR-ring is extension closed.
给出满足主右理想极小条件诣零环的两个充要条件，此类环是扩张闭的。
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