We know what you need to do is take all the molecular partition functions, the transitional ones, and to the N factor. The number of particles.
只要把所有分子平动配分函数相乘,对平动部分,幂次是N,粒子总数。
If you need only to compute the distance and not alignments, as is usually the case, it is easy to reduce this to o (n), since only the previous row is required to compute the next.
如果您只需要计算距离,不需要校准,就像通常情况那样,那么可以很容易地把空间需求降到O (n),因为计算下一行只需要前面一行。
I've addressed the problem of reusability above, but I still need to get rid of that N-to-1 dependency.
我在上面解决了重用性的问题,但是仍然需要避免n对一的依赖关系。
The U.N.Food and Agriculture Organization says more than thirty nations continue to need emergency food assistance.
VOA: special.2009.11.23
We didn't just need that n, not just the principle quantum number that we needed to discuss the energy, but we also need to talk about l and m, as we did in our clicker question up here.
我们不仅需要n,不仅要这个可以,决定能量的主量子数,还需要m和l,就像我们做这道题这样。
So, in terms of finishing our Lewis structure, we're actually not done yet here, even though we have full octets, and we've used up all of our valence electrons, and the reason is because it's c n minus, so we need to make sure that that's reflected in our Lewis structure, so let's put it in brackets here, and put a minus 1.
那么,根据我们的路易斯结构的完成情况,我们实际上还没有全部完成,尽管我们有了填满的“八隅体“,而且用完了所有的价电子,原因就是因为这是一个负离子,我们需要确保我们的路易斯结构能反映出这一点,所以让我们给它加个括号,再加个负一。
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