Thus, for a typical program invocation with N options, the code needs only O(N) [N*O(1)] comparisons—an order of magnitude improvement over the legacy code.

因此，对于具有 N 个选项的典型程序调用，代码只需执行 O(N) [N*O(1)] 比较 — 这是对遗留代码的巨大改进。

youdao

Given the code up there, if I want to move a tower of size n, what do I have to do?

鉴于这里的代码，如果我想移动N个圆盘，我该怎么做？

youdao

So it feels a little backward mentally perhaps, 1 but this is saying, "do this block of code as long as n is less than 1."

所以它感觉可能有点迟缓，但是它指明，“只要n小于,执行这段代码

youdao

You can certainly hit Enter but as we saw-- seen that very quickly makes a mess of your code and such and so backslash N is new line.

你也可以敲回车键-,但是会让你的代码看起来乱七八糟,反斜杠n就是换行符。

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