A=kTlnQ We can take it to be zero. A is equal to k T log Q.

因此可以令它等于零，于是。

youdao

k * n m plus k all times log n is in general going to be much better than k times n.

在普遍情况下要远远好于,实际情况要取决于n和k的取值。

麻省理工公开课 - 计算机科学及编程导论课程节选

Yeah. You're jumping slightly ahead of me, but basically, I'm done when this is equal to 1 right? Because I get down to the base case, so I'm done when b u is over 2 to the k is equal to 1, and you're absolutely right, that's when k is log base 2 of b.

因为这就是最基本的情况了，因此当b/2的k次方等于1的时候就停止了1,你说的太对了，就是k等于b的以2为底的对数的时候,你们都坐的挺靠后的啊，我不知道是不是我讲的不太明白？

麻省理工公开课 - 计算机科学及编程导论课程节选

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