Goes to C with rates k1 and k2.
再到C,以k1和k2的速率。
K2 We find this is k1 times k2.
我们发现这是k1乘以。
Because the rate k1 is very small.
因为速率k1很小。
Suppose f of x, y, z equals k1, that is my equation, s1 and it gives me a solution s1.
假设我的方程是这样,然后给出了一个解。
The power of linearity is F=k1+k2 if I come across f of x, y, z equals k1 plus k2, if it is a linear equation, I don't have to go and solve it all over again.
线性的威力是,一个方程,如果它是个线性方程,那么我就不用再去解他了。
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